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pav-90 [236]
3 years ago
10

1. An item is on sale for 40% off. If the original price of the item is $40, what is the total

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

24

Step-by-step explanation:

find 40% of 40 and then subtract the result from 40

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8 students have 3/4 if a cake how much will each student get if they split it evenly
velikii [3]
Each student gets 1/8 of the cake.

we multiply 1/8 and 3/4. To do that we multiply the numerators together and the denominators together. This gives (1*3)/(8*4) =3/32 of the cake
5 0
3 years ago
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Please help me get this right I don’t know how to do it.
velikii [3]

Answer:

tan∠E=1/3

Step-by-step explanation:

Tangent or opposite/adjacent of angle E is segment HF/3 to solve for HF you can use sine of H opposite over hypotenuse or √8/HF=sin45°. Rearranging the equation you get √8/sin45°=HF and sin45°= 2√2 so √8/2√2=1 HF=1 now you know that tan(∠E)=1/3.

7 0
3 years ago
Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an
VladimirAG [237]

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

  • Cost of cakes = $3.50
  • Cost of Oreos = $2.00
  • The total amount spent = $42.00
<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

3.50x + 2.0y = 42.00

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

3 0
2 years ago
How do i find the area for number 4?
ankoles [38]
<h3>Answer:  41 cm^2</h3>

Explanation:

Form a horizontal line as shown below (see attached image). This forms 2 separate smaller rectangles

  • The bottom rectangle has area of 4*8 = 32 cm^2
  • The top rectangle has area of 3*3 = 9 cm^2

The total area is therefore 32+9 = 41 cm^2

You can say "square cm" or "sq cm" in place of the "cm^2".

5 0
3 years ago
Read 2 more answers
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Shkiper50 [21]

Answer:

a) P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335

b) P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452

c) P(X \geq 8) = 1-P(X

d) P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that X \sim Poisson(\lambda=4)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda=4  , Var(X)=\lambda=2, Sd(X)=2

a. Compute both P(X≤4) and P(X<4).

P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183

P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733

P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465

P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646

P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692

b. Compute P(4≤X≤ 8).

P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595

P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298

P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452

c. Compute P(8≤ X).

P(X \geq 8) = 1-P(X

P(X \geq 8) = 1-P(X

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

4 0
3 years ago
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