The length of DE is 3 bc they are dilated at a ratio of 1 : 1.5
We'll use the following properties of sine and cosine to prove this:



Then it's just a matter of filling it in...
sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =
1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =
1/8(1 - cos160 - cos120 + cos200) =
1/8(1 - cos160 - cos120 + cos160) =
1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16
Given:
The price of bananas can be determined by the equation P=0.25n, where P is the price and n is the number of bananas.
To find:
The constant of proportionality
Solution:
We have,
...(i)
where P is the price and n is the number of bananas.
Price P is directly proportional to the number of bananas. So,

...(ii)
Where, k is the constant of proportionality.
On comparing (i) and (ii), we get

Therefore, the constant of proportionality is 0.25.
Answer:
2°
Step-by-step explanation:
Hello
I see you are very confused by this problem. However, there is an easy way to solve this one.
It has been proved that the sum of all angles in a rectangle is always 180°. Here is a way to prove it:
x y
_______A_________
/\
/ \
/ \
/ \
___/_______ \__
B C
we have two parellel lines xy and BC. It is true that:
xAy = 180°
xAB + BAC + CAy = xAy = 180
xAB = ABC
CAy= ACB
=> ........
I'll let you finish with your great intellect ^_^
HOPE YOU LEARN WITH JOY AND GOOD GRADE
I’ll try my best but sorry if I can’t help a lot I’m not the best at math