1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir2022 [97]
2 years ago
8

What is the greatest common factor for 9x^2 6x and show work

Mathematics
1 answer:
VMariaS [17]2 years ago
6 0

Answer:

3x

Step-by-step explanation:

9x^2 ?6x

9x? 6x

÷3x. ÷3x

=3x and 2x

highest number is 3x

You might be interested in
-(-2)^2<br><br>I can't do it because it confuses me​
Vlad1618 [11]

Answer:

-4

Step-by-step explanation:

4 0
3 years ago
If f(x) = 5x - 7, what is {3)?<br> O A. 22<br> O B. 2<br> O c. 1<br> • D. 8
DerKrebs [107]
<h3>Answer:  8</h3>

Work Shown:

f(x) = 5x - 7

f(3) = 5(3) - 7 .... every x replaced with 3

f(3) = 15 - 7

f(3) = 8

6 0
2 years ago
Read 2 more answers
Perform the indicated operation. (-7) • (-5)<br> -12 <br> 35<br> 12<br> -35
Flauer [41]
Hi,


Equation:

- 7 \times  (- 5)

Multiplying two negatives equals a positive.

( - ) \times ( - ) = ( + )

Now equation looks like:

7 \times 5 = 35

Hope this helps.
r3t40
6 0
3 years ago
Read 2 more answers
Picture attached. help please
Iteru [2.4K]

Answer:

A, D, F.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi
vladimir1956 [14]

Answer:

(a) <em>p</em>-value = 0.043. Null hypothesis is rejected.

(b) <em>p</em>-value = 0.001. Null hypothesis is rejected.

(c) <em>p</em>-value = 0.444. Null hypothesis is not rejected.

(d) <em>p</em>-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a <em>t</em>-test for single mean is used.

The significance level for the test is <em>α</em> = 0.05.

The decision rule is:

If the <em>p - </em>value is less than the significance level then the null hypothesis will be rejected. And if the <em>p</em>-value is more than the value of <em>α</em> then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 11.

The test statistic value is, <em>t</em> = 1.91 ≈ 1.90.

The degrees of freedom is, (<em>n</em> - 1) = 11 - 1 = 10.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 1.90 and degrees of freedom 10 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₀ > 1.91) = 0.043.

The <em>p</em>-value = 0.043 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> < <em>μ₀</em>

The sample size is, <em>n</em> = 17.

The test statistic value is, <em>t</em> = -3.45 ≈ 3.50.

The degrees of freedom is, (<em>n</em> - 1) = 17 - 1 = 16.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of -3.50 and degrees of freedom 16 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The <em>p</em>-value = 0.001 < <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> ≠ <em>μ₀</em>

The sample size is, <em>n</em> = 7.

The test statistic value is, <em>t</em> = 0.83 ≈ 0.82.

The degrees of freedom is, (<em>n</em> - 1) = 7 - 1 = 6.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

<em>Hₐ</em>: <em>μ</em> > <em>μ₀</em>

The sample size is, <em>n</em> = 28.

The test statistic value is, <em>t</em> = 2.13 ≈ 2.12.

The degrees of freedom is, (<em>n</em> - 1) = 28 - 1 = 27.

Use a <em>t</em>-table t compute the <em>p</em>-value.

For the test statistic value of 0.82 and degrees of freedom 6 the <em>p</em>-value is:

The <em>p</em>-value is:

P (t₂₇ > 2.12) = 0.022.

The <em>p</em>-value = 0.444 > <em>α</em> = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0
3 years ago
Other questions:
  • The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit, and the tens digit equals to th
    14·1 answer
  • A triangle has two sides that are perpendicar. Could the triangle be isosceles,epuilateral, or scalene?
    5·2 answers
  • X + 8y &gt; 16 <br> A <br> B <br> C<br> D?
    12·1 answer
  • Solve for e.<br> 9e+4=-5e+14+13e9e+4=−5e+14+13e<br> e=
    12·1 answer
  • In a 45°- 45°- 90° right triangle, the length of the hypotenuse is 15. How long are the legs?
    13·2 answers
  • What’s the answer to the question I can’t figure it out
    12·1 answer
  • Which scatter plot show a non linear association for the data
    9·2 answers
  • Summer read 70 pages in 5 days. 1) How many pages did she read per day? 2) How many days did it take Summer to read 56 pages?
    13·1 answer
  • Please help if possible​
    6·2 answers
  • You earn $35 for washing 7 cars. How much do you earn for washing 4 cars?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!