What number is 150 more than the product of 5 and 4892

Help Me please11111111

Y_Kistochka [10]

Answer:

The first option im pretty sure

Step-by-step explanation:

6 0

2 years ago

X-y=3 in slope intercept form and find x and y intercepts

Dominik [7]

Answer:

x intercept is x=3

y intercept is y=-3

Step-by-step explanation:

We can write this equation in a simpler way to find the values needed. Lets do it. Take:

x-y=3

And sum y in both sides, as we know the equality will maintain:

x-y+y=3+y

x = 3+ y

Now subtract 3 in both sides:

x-3 = y+3-3

x-3=y

So, we can rewrite our equation as y=x-3

The x intercept is a value of x such that the equation in equal to zero; in other words, is the value of x when y is zero. It is also called a zero root. Graphically, its the x value when the function passes trough the x-axis. Lets find if, we nned that:

x-3 = 0

If we sum 3 in both sides:

x-3+3=3

x=3

So, x=3 is x intercept

For finding the y intercept we need the value of y when x is zero. Graphically, is the value of y obtained when the function passes trough the y-axis. So, replace x with 0:

0-3=y

y=-3

Another way to get it is knowing that the y intercept in a polynomial is always the independent term, the one that has no x or y, which in this case is -3.

7 0

2 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$