The domain of f/g
consists of numbers x for which g(x) cannot equal 0 that are in the domains of
both f and g.
Let’s take this equation as an example:
If f(x) = 3x - 5 and g(x)
= square root of x-5, what is the domain of (f/g)x.
For x to be in the domain of (f/g)(x), it must be
in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also
need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore,
there are 3 conditions.
x must be in the domain of f:
f(x) = 3x -5 are in the domain of x and all real numbers x.
x must be in the domain of g:
g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.
g(x) can not be 0: g(x)
= √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.
Hence to x x ≥ 5 and x ≠ 5
so the domain of (f/g)(x) is all x satisfying x > 5.
Thus, satisfying <span>satisfy all
three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x
satisfying x > 5.</span>
Answer: 57r + 42
Step by step explanation:
-3r - 6(-7 - 10r)
Distribute -6 through the parenthesis
-3r + 42 + 60r
Collect the like terms
57r + 42
Answer:
y=6x+1
Step-by-step explanation:
First you must find the slope of the two points...
which then would equal 6
Then you take the slope and put into point-slope form
(y-y1)=m(x-x1)...take one of the points that is given and plug it into this formula.
so I used (-3,19).
(y-19)=6(x--3)
I would then get y-19=6x+18
Add 19 to both sides and you will get y=6x+1
