Answer:
a) ![10[1-e^{-y/3} ] ^{2} e^{-y}](https://tex.z-dn.net/?f=10%5B1-e%5E%7B-y%2F3%7D%20%5D%20%5E%7B2%7D%20%20e%5E%7B-y%7D)
b) ≈ 0.76
Step-by-step explanation:
Given that : Y1 < Y2 < Y3 < Y4 < Y5 are the order statistics of five independent observations
mean of θ = 3
<u>a) Determine the P.d.f of the sample median </u>
P.d.f of sample median ( y3 ) =
attached below is the detailed solution
<u>b) determine the probability that Y4 is < 5 </u>
p( Y4 < 5 ) = G4( 5 )
= 0.7599 ≈ 0.76
attached below is the detailed solutions
Umm it think it would 1/2hx and 1/2hy
idk if im right tho
Answer:
Step-by-step explanation:
<em>13/28 = 195/420</em>
<em>17/30 = 238/420</em>
<em />
<em>So that means that 3 17/30 > 3 13/28</em>
I think the answer is x2 +64 but I hope you get it right good luck ! I hope it is 64 thanks