Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
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Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
2.161616 = 2.161616/1 =21. 61616/10 = 216.1616/100 = 2161.616/1,000
= 21616.16/10,000 = 216161.6/100,000 = 2161616/1,000,000
As a mixed number = 2(161616/100,000)
Answer:
I believe the answer is 152 ft
Step-by-step explanation:
On the side, you would find the area of the square (8x5=40). Then, you would find the area of the triangular front (6x4=24 divded by 2 so it's 12). There are two sides of each, so 24+80=104. Then, you dfind the aarea of the bottom square (6x8=48) and add them all together to make 152
Answer:
Hi! The correct answer is x=1/4+y/2!
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation