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pav-90 [236]
3 years ago
11

Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x=16...

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Step-by-step explanation:

y = kx, where k is a real constant.

When x = 2, y = 7.

=> (7) = k(2), 2k = 7, k = 3.5.

Therefore when x = 16,

y = (3.5)(16) = 56.

The value of y is 56 when x is 16.

bija089 [108]3 years ago
5 0

The formula for direct variation is y = kx

Using the known x and y solve for k:

7 = k2

Divide both sides by 2:

k =7/2 = 3.5

Now solve for y when x = 16:

y = 3.5(16)

y = 56

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1. 
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Given an equation of a circle: x^2-2x+y^2+6y+6=0.

To determine the center and the radius of the equation we must write the above equation in the form :

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4. Not complete


5.

The radius of the pizza is \displaystyle{ \frac{131}{2}ft=65.5ft.

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So the perimeter of one slice is 65.5+65.5+2.62π=131+2.62π

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