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pav-90 [236]
3 years ago
11

Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x=16...

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Step-by-step explanation:

y = kx, where k is a real constant.

When x = 2, y = 7.

=> (7) = k(2), 2k = 7, k = 3.5.

Therefore when x = 16,

y = (3.5)(16) = 56.

The value of y is 56 when x is 16.

bija089 [108]3 years ago
5 0

The formula for direct variation is y = kx

Using the known x and y solve for k:

7 = k2

Divide both sides by 2:

k =7/2 = 3.5

Now solve for y when x = 16:

y = 3.5(16)

y = 56

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The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665. Using a table of values,
tamaranim1 [39]

Answer:

Option A. 5

Step-by-step explanation:

From the question given above, the following data were obtained:

First term (a) = –3

Common ratio (r) = 6

Sum of series (Sₙ) = –4665

Number of term (n) =?

The number of terms in the series can be obtained as follow:

Sₙ = a[rⁿ – 1] / r – 1

–4665 = –3[6ⁿ – 1] / 6 – 1

–4665 = –3[6ⁿ – 1] / 5

Cross multiply

–4665 × 5 = –3[6ⁿ – 1]

–23325 = –3[6ⁿ – 1]

Divide both side by –3

–23325 / –3 = 6ⁿ – 1

7775 = 6ⁿ – 1

Collect like terms

7775 + 1 = 6ⁿ

7776 = 6ⁿ

Express 7776 in index form with 6 as the base

6⁵ = 6ⁿ

n = 5

Thus, the number of terms in the geometric series is 5.

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ArbitrLikvidat [17]

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Step-by-step explanation:

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