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Art [367]
2 years ago
5

How do i work out compound interest?

Mathematics
1 answer:
Artyom0805 [142]2 years ago
6 0

Answer:

The formula for compound interest is P (1 + r/n)^(nt), where P is the initial principal balance, r is the interest rate, n is the number of times interest is compounded per time period and t is the number of time periods.

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A box without a top is made from a rectangular piece of cardboard, with dimensions 27 centimeters by 18 centimeters, by cutting
GaryK [48]
By cutting each corner we have that the resulting dimensions are:
 27 - 2x
 18 - 2x
 Height = x
 Therefore, the volume of the box in terms of the variable x, is given by:
 V (x) = (x) * (27-2x) * (18-2x)
 Answer:
 
The volume of the box in terms of x is:
 
(27-x) (18-x) x
8 0
3 years ago
Read 2 more answers
Thanks! Help is appreciated
Viefleur [7K]

Answer:

D

Step-by-step explanation:

sorry if i am incorrect but that is my best guess

3 0
3 years ago
Read 2 more answers
Angle A and angle B are complementary. m Angle A = 54 and M angle B = 2x+2. What is the m angle B
Gnom [1K]

Answer:

m=17

Step-by-step explanation:

Complementary means they add to equal 90 degrees.

1) 90-A=36

2)36=2x+2

3) Subtract 2 from both sides, 34=2x

4) Divide by 2 17=x

4 0
3 years ago
Two factors of 18 add up to 12. What are they?
stepladder [879]

Answer:

3 and 9

Step-by-step explanation:

The factors of 18 can be listed as

1, 2, <u>3</u>, 6, <u>9</u>, 18

The two which sum to 12 are 3 and 9

7 0
3 years ago
A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
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