Answer:
a. 12 feet b. 12 feet 0.5 inches c. 8.33 %
Step-by-step explanation:
a. How far out horizontally on the ground will it protrude from the building?
Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.
So, by ratios rise/run = 1/12 = 12/x
1/12 = 12/x
x = 12 × 12
x = 144 inches
Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet
b. How long should the ramp be?
The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.
So, L = √(12² + 144²)
= √[12² + (12² × 12²)]
= 12√(1 + 144)
= 12√145
= 12 × 12.042
= 144.5 inches
Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches
c. What percent grade is the ramp?
The percentage grade of the ramp = rise/run × 100 %
= 12 inches/144 inches × 100 %
= 1/12 × 100 %
= 0.0833 × 100 %
= 8.33 %
Two lines are parallel if they have the same slope. Computing for the slope of line segment ab and line segment cd using m=(y2-y1)/x2-x1):
m of ab=(2-1)/(2-1)=1 m of cd=<span>(4-3)/(4-3)=1
Since line segment ab and line segment cd have the same slope which is 1, then they are said to be parallel. </span>
Answer:
Since, In Quadrilaterals KLMN and quadrilateral WXYZ,
Sides Kl, LM, MN and NK are corresponding to the sides WX, XY, YZ and ZW respectively.
Also, If two shapes are similar the ratio of their corresponding sides must be same are in same proportion,
Here, Quadrilateral KLMN is similar to quadrilateral WXYZ,
Therefore,
Which is the required proportion that must be true for the given figure.
I think it's the first one. Two units right and three units down.
Answer:
So the numbers are 12 and -3.
Step-by-step explanation:
In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:
x - y = 15
Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:
(1/3)*(x+y) = x/4
Since we now have two equations and two variables we can solve for x and y. From the first equation we have:
y = x - 15
Using this expression for the value of y in the second equation:
(1/3)*(x + x - 15) = x/4
(1/3)*(2*x - 15) = x/4
2*x - 15 = 3*x/4
2*x - 3*x/4 = 15
(8*x - 3*x)/4 = 15
5*x/4 = 15
5*x = 60
x = 60/5 = 12
y = x - 15 = 12 - 15 = -3
So the numbers are 12 and -3.
