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Leya [2.2K]
3 years ago
9

Leila, Charlie, and Joe have a total of $144 in their wallets. Joe has 4 times what Leila has. Charlie has $6 more than Leila. H

ow much does each have?
Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

The amounts of money each has are:

Joe = $92

Charlie = $29

Leila = $23

Step-by-step explanation:

To solve this, we will convert the statements into an equation, and use that to solve for the unknowns, as follows:

total amount = $144

Let Leila's share be S

Joe's share = 4 times Leila's = 4S

Charlie's share = $6 + Leila's share = 6 + S

Joe's share + Charlie's Share + Leila's Share = $144

4S + (6 + S) + S = 144

4S + 6 + S + S = 144

4S + 2S + 6 = 144

6S + 6 = 144

6S = 144 - 6 = 138

S = 138 ÷ 6 = $23

Therefore Leila's share 'S' = $23

Joe share= 4S = 4 × 23 = $92

Charlie's share = 6 + 23 = $29

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Answer:

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The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2

<h3>How to determine the zeros of the function?</h3>

The function is given as:

f(x) = x^3 + 3x^2 + 2x

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Read more about zeros of function at

brainly.com/question/20896994

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