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frosja888 [35]
3 years ago
7

It takes a train 8 hours to travel a distance of 216 km. What is the average speed of the train?

Mathematics
1 answer:
Contact [7]3 years ago
3 0

(S=D/T)S=216KM, T=8HOURS : 216/8=27KM/HOUR

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Each member of the team will get two thirds of an orange.
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2 years ago
Find 9% of $2005.00 <br> Can anyone answer this ASAP!!!
Ket [755]

Step-by-step explanation:

= \frac{9}{100} × 2005

= \frac{3609}{20}

= 180\frac{9}{20} or 180.45

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8 0
2 years ago
In XYZ, XY=XZ<br> Find the length of XY of XYZ if XY=2a, YZ=3a+1, andXZ=5a-12
lorasvet [3.4K]

Answer: XY = 8

Step-by-step explanation:

The diagram of the triangle XYZ is shown in the attached photo.

XY=XZ. This means that two sides of the triangle are equal. Two angles are also equal. It means that the triangle XYZ is an isosceles triangle.

Since XY=XZ, then

2a = 5a - 12

Subtracting 2a from both sides of the equation,

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5 0
2 years ago
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Eduardwww [97]

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7 0
3 years ago
Find the area of the region that lies under the parabola y=5x - x^2, where 1≤x≤4. I would definitely like to see some work :)
Elena L [17]

Answer:

  16.5 square units

Step-by-step explanation:

You are expected to integrate the function between x=1 and x=4:

  \displaystyle\text{area}=\int_1^4{(5x-x^2)}\,dx=\left.\left(\dfrac{5}{2}x^2-\dfrac{1}{3}x^3\right)\right|_{x=1}^{x=4}\\\\=\dfrac{5(4^2-1^2)}{2}-\dfrac{4^3-1^3}{3}=37.5-21=\boxed{16.5}

__

<em>Additional comment</em>

If you're aware that the area inside a (symmetrical) parabola is 2/3 of the area of the enclosing rectangle, you can compute the desired area as follows.

The parabolic curve is 4-1 = 3 units wide between x=1 and x=4. It extends upward 2.25 units from y=4 to y=6.25, so the enclosing rectangle is 3×2.25 = 6.75 square units. 2/3 of that area is (2/3)(6.75) = 4.5 square units.

This region sits on top of a rectangle 3 units wide and 4 units high, so the total area under the parabolic curve is ...

  area = 4.5 +3×4 = 16.5 . . . square units

4 0
2 years ago
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