The valid probability distributions are the ones in options C and D.
<h3>
Which of the following are valid probability distributions?</h3>
For discrete random variables with probabilities p₁, p₂, ..., pₙ, there are two rules:
- All of these probabilities are numbers between 0 and 1.
- p₁ + p₂ + ... + pₙ = 1.
So, for the first rule we can discard the first option, where we have negative probabilities.
To check the other 4 options, just add the probabilities and see if the addition gives 1.
The options that add up to 1 are C and D, so these two are the correct options.
D: 1/5 + 1/10 + 1/10 + 1/10 + 1/5 + 1/10 + 1/10 + 1/10 = 1
C: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1
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4 Americans can arrange themselves in 4! ways.similarly ,3 Frenchmen can arrange themselves in 3! ways.3 Englishmen can arrange themselves in 3! ways.now these 3 groups of same nationality people can be arranged among themselves in 3! ways.so total number of ways = 3!4!3!3!
X - number of the adults, y - number of children;
The system is:
10 x + 6 y = 3292
x + y = 350 => y = 350 - x
----------------------
10 x + 6 * ( 350 - x ) = 3292
10 x + 2100 - 6 x = 3292
4 x = 3292 - 2100
4 x = 1192
x = 1192 : 4
x = 298
y = 350 - 298
y = 52
Answer:
There were 598 adults and 52 children at the showing.
Answer:
A. x=6
Step-by-step explanation:
x=√10²-8²=√100-64=√36=6
Answer:
<h2><u>Answer</u><u> </u><u>:</u><u>-</u></h2>
Surface area of sphere = 4 π r²
154 = 4 × 22/7 × r²
154 = 88/7 × r²
154 × 7/88 = r²
12.25 = r²
3.5 = r
Now
Volume of sphere = 4/3 × π r³
Volume = 4/3 × 22/7 × (3.5)³
Volume = 88/21 × 42.875
Volume = 154 cm³
Volume of sphere = Volume of cube
Volume of cube = 154 cm³
