Answer:
-1.71 J/K
Explanation:
To solve this problem we use the formula
ΔS = n*ΔH/T
Where n is mol, ΔH is enthalpy and T is temperature.
ΔH and T are already given by the problem, so now we calculate n:
Molar Mass C₂H₅OH = 46 g/mol
2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol
Now we calculate ΔS:
ΔS = 0.0589 mol * −4600 J/mol / 158.7 K
ΔS = -1.71 J/K
Answer:
C. Their properties change completely.
Explanation:
The electron configurations of the elements show a periodic variation with increasing atomic number. Consequently, there are also periodic variations in physical and chemical behavior.
When atoms interact to form a chemical bond, they combine in order to <u>achieve a more stable electron configuration.</u> As a consequence, the compounds formed exhibit completely different properties.
For example, when solid magnesium burns in air, it forms both magnesium oxide and magnesium nitride, which are gases.
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Answer:
a. Oxygen is the limiting reagent. 
b. 
%
Explanation:
Hello,
a. Limiting reagent and sulfur trioxide's theoretical yield.
At first, we must compute the involved moles for both sulfur dioxide's and oxygen's as follows, considering the volumes in liters and the pressure in atm of 50.0mmHg*1atm/760mmHg=0.0658atm:
Afterwards, by considering the properly balanced chemical reaction:
We compute the oxygen's moles that completely reacts with the previously computed 
moles of 
as follows:
That result let us know that the oxygen is the limiting reagent since just 
moles are available in comparison with the 
moles that completely would react with moles of .
Now, to compute the theoretical yield of sulfur trioxide, we apply the following stoichiometric relationship:
b. Percent yield.
At first, we must compute the collected (real) moles of sulfur trioxide:
Finally, we compute the percent yield:
%
%
%
Best regards.
Answer:
pressure
Explanation:
gas convert to liquid at high pressure.
