Answer:
I think the answer is D.coral reef, neritic zone
Explanation:
Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa
Explanation:
The question requires us to calculate the pressure, in kPa, connsidering the following information:
<em>number of moles = n = 4.20mol</em>
<em>volume of gas = V = 15.0L</em>
<em>temperature of gas = T = 280.0 K</em>
We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:
Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:
<em>R = 8314.46 L.Pa/K.mol</em>
Applying the values given by the question to the rearranged equation above, we'll have:
Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.
The empirical formula is C₇H₆O₂.
Assume that you have 100 g of the compound.
Then you have 68.84 g C and 4.962 g H.
Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.
Now, we must convert these masses to moles and find their ratios.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u> ×2</u> <u>Integers</u>
C 68.84 5.732 3.501 7.001 7
H 4.962 4.923 3.006 6.012 6
O 26.20 1.638 1 2 2
The empirical formula is C₇H₆O₂.
Answer:
the culotte, the fulminant capsule and the sheath or cap together with remains of powder
Explanation:
A bullet has a nose, sheath or casing, a short propellant charge, and a capsule.
All these components are part of the vouchers. The classification of these is in metallic and semi-metallic.
Answer:
The balanced equation is given below:
CH4 + 2O2 → 2H2O + CO2
The coefficient of O2 and CO2 are 2 and 1 respectively.
Explanation:
CH4 + O2 → 2H2O + CO2
The above equation can be balanced as follow:
There are a total of 4 atoms of O on the right side and 2 atoms on the left. It can be balance by putting 2 in front of O2 as shown below:
CH4 + 2O2 → 2H2O + CO2
Now we can see that the equation is balanced.
Therefore, the coefficient of O2 and CO2 are 2 and 1 respectively.