Question

A sample of N2 gas occupied 9.20 L at 21 degrees C and 0.959 atm. If the pressure is tuned to 1.15 atm at constant temperature what is the newly occupied volume

Answer 1

Newly occupied volume is 7.672L by N2 gas.  

Explanation:-

Given  

V= 9.20 L, T(i) = T (f) = 294 K, P (i) = 0.959 atm, P (f) = 1.15 atm

To Find V (f)  

Solution

According to the gas equation  

PV= nRT

Where P=Pressure

V=Volume

n=No of moles

R=Universal gas constant

T=Temperature

Also we know the relation between pressure, volume and temperature as

PV/T = constant

$\frac{p(i) V(i) \times p(f) V(f)}{T(i) \times T(f)}$

$V(f)=[P(i) V(i) T(f)] \div[T(i) P(f)]$

Where P(i)V(i)/T(i) are the initial values of Pressure, Volume and Temperature.

P(f)V(f)/T(f) are the final values of Pressure, Temperature and Volume.

Substitute the known values in the equation we get

= $\frac{0.959 \times 9,2 \times 294}{294 \times 1.15}$

=$2574.94 \div 338.1$

= 7.672 L

Thus the final volume of the system is 7.672 L