Answer:
0.25 kilometers
Step-by-step explanation:
250 meters = 0.25 kilometers
I hope this helps you!
Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
therefore
The time of a commercial airplane is
t+140=140+140=280 minutes
<span> 2% of 8386 is 167.72</span>
Answer:Missing: 3y² Бу
Step-by-step explanation:
Answer:
<em>EX=2.68 ≈ 3</em>
<em>Lakeside Olds should expect 3 automobiles lined up at opening</em>
Step-by-step explanation:
<u>Expected Value of a Discrete Probability Distribution</u>
Given a discrete probability distribution of values
x={x1,x2,x3...,xn}
And probabilities
p={p1,p2,p3,...,pn}
Provided the sum of all probabilities is 1, then the expected value of the distribution is
EX =
The data refers to the number of automobiles lined up at Lakeside Olds at opening time for service:
x={1,2,3,4}
And probabilities
p={ 0.40 , 0.03 , 0.06 , 0.51 }
Checking the sum: 0.40 + 0.03 + 0.06 + 0.51 = 1
Now compute the expected value
EX= 1*0.40+2*0.03+3*0.06+4*0.51
EX=2.68 ≈ 3
Lakeside Olds should expect 3 automobiles lined up at opening