Answer:
a)
degrees
b) 
Step-by-step explanation:
An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

a) Calculate I at (T ,H) = (95, 50).
degrees
(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.
This is the partial derivative of I in function of T, that is
. So



Answer:
Approximately 3 grams left.
Step-by-step explanation:
We will utilize the standard form of an exponential function, given by:

In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.
Our initial amount <em>a </em>is 185 grams.
So, by substitution, we have:

Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.
We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:

Evaluate:

So, after six half-lives, there will be approximately 3 grams left.
Answer:
1/2 (x+5) = 36 should be the equation that is used to determine how many rocks George started with.
Step-by-step explanation:
Let 'x' be the number of rocks George had.
As George gave, after getting 5 new rocks, half of his rock collection to Susan which is = 36 rocks
It means after getting 5 new rocks George's total rocks = 72
Given that he gave half collection to Susan = 36
Thus, before inducting 5 new rocks Georg's total rocks were = 67
Thus,
1/2 (x+5) = 36 should be the correct equation.
solving
1/2 (x+5) = 36
Multiplying both sides by 2
1/2 (x+5) × 2 = 36 × 2
x+5 = 72
x = 72 - 5
x = 67
Thus, before getting 5 new rocks, the number of rocks George had = 67
Therefore,
1/2 (x+5) = 36 should be the equation that is used to determine how many rocks George started with.
For this case we have an equation of the form:
y = A * (b) ^ t
Where,
A: initial amount
b: decrease rate
t: time in years.
Substituting values we have:
7 = A * (0.5) ^ ((1/20) * t)
For t = 45 years we have:
7 = A * (0.5) ^ ((1/20) * 45)
Clearing A:
A = 7 / ((0.5) ^ ((1/20) * 45))
A = 33.3
Answer:
the density of the substance when it was deposited 45 years ago was:
A = 33.3 milligrams per square centimeter
Answer:
i believe the answer 602
Step-by-step explanation:
tell me if im wrong but hoped I helped:)