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mestny [16]
3 years ago
8

If 2,575J of heat is added to a 250g piece of silver, the change in temperature of the silver will be 43.6 °C? What is the speci

fic heat of of silver
Physics
2 answers:
qaws [65]3 years ago
7 0

Answer:

0.236 C

Explanation:

LUCKY_DIMON [66]3 years ago
6 0

Answer:

58.56°C

Explanation:

Brrrrrrrrrrrrrr

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Two pucks collide with each other. after the collision they do not stick together. is kinetic energy conserved in the collision?
miv72 [106K]
Since they do not stick after collision hence collision is elastic. In elastic collision, both momentum and kinetic energy is conserved because in this type of collision, first body deforms but then quickly regains its former shape and transfers its kinetic energy to the second pluck.
So kinetic energy is conserved.
5 0
3 years ago
One possible explanation for a galaxy's type invokes the angular momentum of the protogalactic cloud from which it formed. Suppo
garik1379 [7]

Answer:

A spiral galaxy

Explanation:

6 0
3 years ago
Energy from the Sun is transferred from the Earth’s surface to the atmosphere, resulting in
natali 33 [55]

Answer:

C make a the most sense hopefully this helps

4 0
3 years ago
Read 2 more answers
In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th
Georgia [21]

Explanation:

Given that,

Frequency in the string, f = 110 Hz

Tension, T = 602 N

Tension, T' = 564 N

We know that frequency in a string is given by :

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{m/L}}, T is the tension in the string

i.e.

f\propto\sqrt{T}

\dfrac{f}{f'}=\sqrt{\dfrac{T}{T'}}, f' is the another frequency

{f'}=f\times \sqrt{\dfrac{T'}{T}}

{f'}=110\times \sqrt{\dfrac{564}{602}}

f' =106.47 Hz

We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :

f_b=|f-f'|

f_b=|110-106.47|

f_b=3.53\ beats/s

So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.

8 0
3 years ago
A child bounces a 48 g superball on the sidewalk. the velocity change of the superball is from 26 m/s downward to 17 m/s upward.
Nataly_w [17]
By definition we have the momentum is:
 P = m * v
 Where,
 m = mass
 v = speed
 Before the impact:
 P1 = (0.048) * (26) = 1.248 kg * m / s
 After the impact:
 P2 = (0.048) * (- 17) = -0.816 Kg * m / s.
 Then we have that deltaP is:
 deltaP = P2-P1
 deltaP = (- 0.816) - (1,248)
 deltaP = -2,064 kg * m / s.
 Then, by definition:
 deltaP = F * delta t
 Clearing F:
 F = (deltaP) / (delta t)
 Substituting the values
 F = (- 2.064) / (1/800) = - 1651.2N
 answer:
 the magnitude of the average force exerted on the superball by the sidewalk is 1651.2N
3 0
4 years ago
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