Ask question

Ask question

All categories

3 years ago

8

If 2,575J of heat is added to a 250g piece of silver, the change in temperature of the silver will be 43.6 °C? What is the speci

fic heat of of silver

2 answers:

qaws [65]3 years ago

7 0

Answer:

0.236 C

Explanation:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

58.56°C

Explanation:

Brrrrrrrrrrrrrr

You might be interested in

The two basic units of weight in the metric system is the___?

Alika [10]

Answer:

The two basic units of weight in the metric system is the?

The gram and kilogram is the Correct Answer...

3 0

3 years ago

Electromagnetic waves all move at the same wave speed. which of these offer solutions to slowing them down select all that apply

Lelechka [254]

option c...have the waves move thru the vacuum or space

6 0

3 years ago

A flywheel with radius of 0.400 mm starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2rad/s2.

charle [14.2K]

Answer: $0.00024\ m/s^2$

Explanation:

Given

Radius of flywheel is $r=0.4\ mm$

Angular acceleration $\alpha=0.6\ rad/s^2$

For no change in radius, tangential acceleration is given as

$\Rightarrow a_t=a\lpha \times r$

Insert the values

$\Rightarrow a_t=0.6\times 0.4\times 10^{-3}\ m/s^2\\\Rightarrow a_t=2.4\times 10^{-4}\ m/s^2\ \text{or}\ 0.00024\ m/s^2$

5 0

3 years ago

A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?

Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave = 330m/s

Wavelength = 0.372m

Unknown:

Frequency = ?

Solution:

To solve this problem, we use the expression below:

Speed = Frequency x wavelength

330 = Frequency x 0.372

Frequency = 887.1Hz

5 0

3 years ago

A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a

Elza [17]

Answer:

$\dfrac{dz}{dt}=0.65\ ft/s$

Explanation:

Given that

x= 150 ft

$\dfrac{dy}{dt}= 7\ ft/s$

y= 14 ft

From the diagram

$z^2=x^2+y^2$

When ,x= 150 ft and y= 14 ft

$z^2=150^2+14^2$

$z=\sqrt{150^2+15^2}$

z=150.74 ft

$z^2=x^2+y^2$

By differentiating with respect to time t

$2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}$

$z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}$

Here x is constant that is why

$\dfrac{dx}{dt}=0$

$z\dfrac{dz}{dt}= y\dfrac{dy}{dt}$

Now by putting the values in the above equation we get

$150.74\times \dfrac{dz}{dt}=14\times 7$

$\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s$

$\dfrac{dz}{dt}=0.65\ ft/s$

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

5 0

3 years ago