Restaurants sales totaled $38,676 for the week your customer count was $7,325 what did the average customer spend for the week

1 answer:

4 0

I’m assuming the 7325 are the number of people, since you write it in dollars.

$38676 that week / 7325 people
= $54.78 per person

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A study of the impact of executive networking on firm performance measured firm performance as annual return on equity (ROE), r

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Answer:

The value of ROE that will be exceeded by 78% of the firms is -1.77%.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma,$ the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The mean ROE for the firms studied was 14.93% and the standard deviation was 21.74%. This means that $\mu = 0.1493, \sigma = 0.2174$