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Alja [10]
3 years ago
6

If t = the tens digit and u = the ones digit, which expression shows the value of reversing the digits in a two digit number? u

+ t 10u + t u + 10t
Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:. 10u + t

Step-by-step explanation:

The value of the units digit is multiplied by 10 when it moves to the tens place.

vlabodo [156]3 years ago
5 0

Answer:

10u+t

Step-by-step explanation:

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Hannah is 10 and 3/4 years old

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Answer is 0.5
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Step-by-step explanation:

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4 0
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Amy's math notebook weighs 1/2 pound, her science notebook weighs 7/8 pound, and her history notebook weighs 3/4 pound. What are
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Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
4 0
3 years ago
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