Can someone help me with this problem?
1 answer:
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The outlier of a dataset is a data element that is relatively far from the remaining data elements
- <em>99 is an outlier of pet group</em>
- <em>See attachment for the parallel box plots</em>
<u>(a) Prove that 99 is an outlier for Pet</u>
We have:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
The quartiles positions are:
So, we have:
From the pet group:
The data elements at the 4th and 12th positions are 68 and 79
So, we have:
The lower and upper limits of the outlier are:
So, we have:
This means that data below 51.5 or above 95.5 are outliers.
<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>
<u>(b) The parallel box plot</u>
The three groups are:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>
<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>
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See attachment for the parallel box plots
Read more about box plots and outliers at:
Answer:
Step-by-step explanation:
The formula of an area of a parallelogram:
b - base
h - height
We have:
base₁ = 9.8 in
base₂ = 10 in
height₁ = 5.6 in
height₂ = h
The area of a parallelogram:
and
Therefore we have the equation:
Substitute:
<em>divide both sides by 10</em>