Answer:C:Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy
Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy.
Although the initial energy (potential energy is preserved), the energy of deformation as the ball strikes a surface creates energy dissipation in the form of frictional heat and audible sound energy.
Every time the ball bounces, its height will be less than its previous height.
Explanation:
During the first phase of acceleration we have:
v o = 4 m/s; t = 8 s; v = 13 m/s, a = ?
v = v o + a * t
13 m/s = 4 m / s + a * 8 s
a * 8 s = 9 m/s
a = 9 m/s : 8 s
a = 1.125 m/s²
The final speed:
v = ?; v o = 13 m/s; a = 1.125 m/s² ; t = 16 s
v = v o + a * t
v = 13 m/s + 1.125 m/s² * 16 s
v = 13 m/s + 18 m/s = 31 m/s
The relationship between wavelength

, frequency f and speed of light c for an electromagnetic wave is

Using the data of the problem, we find
Take the stone's position at ground level to be the origin, and the downward direction to be negative. Then its position in the air
at time
is given by

Let
be the depth of the well. The stone hits the bottom of the well after 5.00 s, so that

Answer:
<u><em>0.03 m/s</em></u>
Explanation:
<em>Applying law of conservation of momentum, </em>
- <em>m₁v₁ + m₂v₂ = (m₁ + m₂)v</em>
- <em>0.105(24) + 75(0) = (0.105 + 75)v</em>
- <em>75.105v = 2.52</em>
- <em>v = 2.52/75.105</em>
- <em>v = </em><u><em>0.03 m/s</em></u>