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labwork [276]
3 years ago
9

A fly sits on a potter's wheel 0.30 m from its axle. The wheel's rotational speed decreases from 4.0 rad/s to 2.0 rad/s in 5.0 s

. Determine the wheel's average rotational acceleration. Express your answer in radians per second squared. Enter positive value if the rotational speed increases and negative value if the rotational speed decreases.

Physics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer: The wheel's average rotational acceleration is -0.4 radians per second squared (rad/s^2)

Explanation: Please see the attachments below

sesenic [268]3 years ago
5 0

Answer:

The average rotational acceleration is -0.4 rad/s²

Explanation:

Given:

w₁ = initial rotational speed = 4 rad/s

w₂ = final rotational speed = 2 rad/s

t = time = 5 s

The average rotational acceleration is:

w_{average} =\frac{w_{2}-w_{1}  }{t} =\frac{2-4}{5} =-0.4rad/s^{2}

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a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.

Explanation:

For an inelastic collision:

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Using these facts, let's now analyze each statement given.

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.  --> TRUE. Since the total momentum is conserved, we can write:

p_1 = p_1'+p_2'

where

p_1 is the initial momentum of the 5-kg ball

p_1' is the final momentum of the 5-kg ball

p_2' is the final momentum of the 10-kg ball

The equation can be rewritten as

p_1-p_1'=p_2'

which is equivalent to

-\Delta p_1 = \Delta p_2

which means that the magnitude of the change of momentum of the two balls is the same.

b. Both balls lose all their momentum since the collision is inelastic.  --> FALSE, the 10-kg ball gains momentum, so it does not lose it.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.  --> TRUE. We already said that the magnitude of the change in momentum of the two balls is the same. However, it can be written as

\Delta p = m\Delta v

where m is the mass of the ball and \Delta v its change in velocity. Therefore, the 5-kg ball (which has smaller mass) will have a larger \Delta v, so a larger change in velocity.

d. The magnitude of the change of velocity the 5-kg ball experiences is equal to that of the 10-kg ball.  --> FALSE, as we discussed in c).

e. The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball. --> FALSE, as we discussed in c).

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brainly.com/question/9484203

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