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creativ13 [48]
3 years ago
12

The elementary particle called a muon is unstable and decays in about 2.20μs2.20μs , as observed in its rest frame, into an elec

tron, a neutrino, and an antineutrino. What lifetime do you observe for muons approaching you at 0.9270.927 the speed of light?
Physics
1 answer:
vredina [299]3 years ago
3 0

Answer:

5.865 μs

Explanation:

t₀ = Time taken to decay a muon = 2.20 μs

c = Speed of Light in vacuum = 3×10⁸ m/s

v = Velocity of muon = 0.927 c

t = Lifetime observed

Time dilation

t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-\frac{(0.927c)^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-0.927^2}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{0.140671}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{0.3750}\\\Rightarrow t=5.865\times 10^{-6}\ seconds

∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs

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A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with ju
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Explanation:

An impulse results in a change of momentum

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FΔt = mΔv

F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)

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F = m(v₀)/t₁

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We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.

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2 years ago
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Marine science- question- what is climate change?
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Answer:

Defined below

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Answer:

The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x 10^{-4} N/C

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    = 1.01 x 10^{-4} N/C

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3 years ago
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