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Studentka2010 [4]
3 years ago
5

What is the slope of the line on the graph? Enter your answer in the box.

Mathematics
2 answers:
pshichka [43]3 years ago
8 0
I know this is WAY late.. but this is for whoever finds this in the future.

The answer is: -2

:)
HACTEHA [7]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

i took the test

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PLEASE HELP ASAP!
wolverine [178]

Answer:

1. slope

2. slope

3. slope

4. y intercept

5. slope

6. it crosses the x axis

7. when the value of y is zero

8. when the form is y = something

9. when the form is x = something

10. Positive slope

11. Negative slope

12. y=x

13. Slope Intercept form

14. Standard form

3 0
3 years ago
What is the mean of -3, 4, 8, -1, -4, -2, 0, 2, 5, 2, -3, 1
Rom4ik [11]

Answer:

3/4 or .75

Step-by-step explanation:

The mean means the average so you would add up all the numbers then divide by how many numbers there are

-3+4+8+-1+-4+-2+0+2+5+2+-3+1= 9

9/12= 3/4 or .75

depends whether or not you want it in fraction or decimal form

3 0
3 years ago
Read 2 more answers
Please help me with this i need help she is gonna call my mom again!!!​
telo118 [61]

Answer:

1. 15

2. -23

3. -16

Step-by-step explanation:

1. Find h(-8)

h(t) = \frac{5}{4}(4 - t)

h(-8) = \frac{5}{4}(4 -(-8))

h(-8) = \frac{5}{4}(4+8) =\frac{5}{4}(12)=5(3)=15

2. What is the value of g(-3)

g(x) = 4(x - 5) + x^{2}

g(-3) = 4(-3 - 5) -3^{2}

g(-3) = 4(-8) + 9

g(-3) = -32 + 9

g(-3) = -23

3. Find f(10)

f(x) = 14 - 3x

f(10) = 14 - 3(10)

f(10) = 14 - 30

f(10) = -16

7 0
3 years ago
Read 2 more answers
This graph shows a portion of an odd function.
nexus9112 [7]

9514 1404 393

Answer:

  • -2
  • -1
  • -2
  • -3

Step-by-step explanation:

An odd function is symmetrical about the origin:

  f(-x) = -f(x)

So, ...

  f(-2) = -f(2) = -2

  f(-3) = -f(3) = -1

  f(-4) = -f(4) = -2

  f(-6) = -f(6) = -3

6 0
2 years ago
Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.
Tasya [4]

Answer:

The answer is " \bold{\frac{7}{2}}"

Step-by-step explanation:

Given value:

\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0

Find:

area=?

calculation:

\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx  + \int_{0}^{1} (4x+3x^2-x^3) dx  \\\\

        =  -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\=  -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\=  ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\=  ( \frac{3}{4}) + (\frac{11}{4})\\\\=   \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\

7 0
3 years ago
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