Answer:
2522g
Explanation:
8Fe + S8 —> 8FeS
From the question,
8moles of Fe required 1mole of S8.
Therefore, Xmol of Fe will require 5.65mol of S8 i.e
Xmol of Fe = 8 x 5.65 = 45.2moles
Now we need to covert 45.2moles to gram. This is illustrated below below:
Molar Mass of Fe = 55.8g/mol
Number of mole of Fe = 45.2moles
Mass of Fe =?
Mass = number of mole x molar Mass
Mass of Fe = 45.2 x 55.8
Mass of Fe = 2522g
Therefore, 2522g of Fe is needed for the reaction.
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
Answer:
dilute solution
A solution containing less solute than the equilibrium amount is called a dilute solution. The solvent has a limited capacity to dissolve a solute.
Explanation:
