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Pavel [41]
3 years ago
11

The two algae seen here are classified as green algae. That means they make their own food by photosynthesis. The algae on the l

eft is one-celled, or unicellular. The algae on the right is many-celled, or multicellular.
How are these two types of algae different?
Question 5 options:

Only the the multicellular algae contains a chloroplast.


They are different only in how many cells make up each algae.


Only the multicellular algae has chlorophyll for photosynthesis.


The multicellular algae cel has many more parts than the unicellular algae.

Chemistry
2 answers:
ohaa [14]3 years ago
6 0

Answer:

C

Explanation:

Unicellular algae can't do photosynthesis because it is a single cell organisms, therefore the answer is C

vodka [1.7K]3 years ago
4 0

Answer:

b

Explanation:

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The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH. It requires 18.
olchik [2.2K]

Answer:

Approximately 0.291\; \rm M (rounded to two significant figures.)

Explanation:

The unit of concentration \rm M is the same as \rm mol \cdot L^{-1} (moles per liter.) On the other hand, the volume of both the \rm NaOH solution and the original \rm HCl solution here are in milliliters. Convert these two volumes to liters:

  • V(\mathrm{NaOH}) = 18.2\; \rm mL = 18.2 \times 10^{-3}\; \rm L = 0.0182\; \rm L.
  • V(\text{$\mathrm{HCl}$, original}) = 10.0\; \rm mL = 10.0\times 10^{-3}\; \rm L = 0.0100\; \rm L.

Calculate the number of moles of \rm NaOH in that 0.0182\; \rm L of 0.160\; \rm M solution:

\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}.

\rm HCl reacts with \rm NaOH at a one-to-one ratio:

\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l).

Coefficient ratio:

\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1.

In other words, one mole of \rm NaOH would neutralize exactly one mole of \rm HCl. In this titration, 0.291\; \rm mol of \rm NaOH\! was required. Therefore, the same amount of \rm HC should be present in the original solution:

\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}.

Calculate the concentration of the original \rm HCl solution:

\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M.

5 0
3 years ago
Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Giv
RSB [31]

Answer: No reaction occurs

Explanation:.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

Al(C_2H_3O_2)_3(aq)+3LiNO_3(aq)\rightarrow Al(NO_3)_3(aq)+3LiC_2H_3O_2(s)

The complete ionic equation is;

Al^{3+}(aq)+3C_2H_3O_2^-(aq)+3Li^+(aq)+3NO_3^-(aq)\rightarrow Al^{3+}(aq)+3NO_3^-(aq)+3Li^+(aq)+3C_2H_3O_2^-(aq)

The ions which are present on both the sides of the equation are are not involved in net ionic equation.

Hence, there is no net reaction.

5 0
3 years ago
What is the definition of RNA<br>Messenger RNA<br>and <br>Ribosome?<br><br>​
IceJOKER [234]
You can find this on google easily
4 0
3 years ago
When Na and Cl combine to form a compound, which atom(s) will become a cation?
vivado [14]
Na only because cation is a positive ion whole cl is a negative ion in anion
8 0
3 years ago
Read 2 more answers
The reaction 2NO(g) + O2(g) → 2NO2(g)
Marina86 [1]

Answer:

could be reduced by one-quarter.

Explanation:

5 0
2 years ago
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