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3 years ago

Given the following equation: 8 Fe + S8 —> 8 FeS what mass of iron is needed to react with 5.65 mol of sulfur S8

Chemistry

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

2522g

Explanation:

8Fe + S8 —> 8FeS

From the question,

8moles of Fe required 1mole of S8.

Therefore, Xmol of Fe will require 5.65mol of S8 i.e

Xmol of Fe = 8 x 5.65 = 45.2moles

Now we need to covert 45.2moles to gram. This is illustrated below below:

Molar Mass of Fe = 55.8g/mol

Number of mole of Fe = 45.2moles

Mass of Fe =?

Mass = number of mole x molar Mass

Mass of Fe = 45.2 x 55.8

Mass of Fe = 2522g

Therefore, 2522g of Fe is needed for the reaction.

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The air molecules in the compressions of the second wave are denser, so the sound is louder.

<h3>What is a sound wave?</h3>

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1 year ago

Can someone help me find the answer?

valentina_108 [34]

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3 years ago

The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28

ivanzaharov [21]

<u>Answer:</u> The mass of second isotope of indium is 114.904 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

<u>For isotope 1:</u>

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

<u>For isotope 2:</u>

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

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3 years ago

Analyze complete and balance the following equation co2(g)+hcl(aq)

Anna007 [38]

Answer:

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2 years ago

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valentina_108 [34]

Answer:

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