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Vaselesa [24]
4 years ago
15

Pls help me i have to turn this in in less than 15 min.

Chemistry
2 answers:
Aleksandr-060686 [28]4 years ago
7 0

Answer:

Boiling point!

Explanation:

Distilled water is capable of being heated beyond the normal boiling point due to absence of dissolved impurities which provide nucleating points at the normal boiling point.

If you enjoyed my answer, I'd appreicate a Thanks and a rating!

Have a great day!

SCORPION-xisa [38]4 years ago
5 0

Answer:

Last one

Explanation:

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The characteristic properties of an acid are due to the presence of what ions?
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The presence of hydrogen ions. H+
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Which substance is a reducing agent?<br><br> A. CO<br> B. F2<br> C. CO2<br> D. H2O2<br> E. FeSO4
IRISSAK [1]

H2O2

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3 years ago
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In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte
siniylev [52]

Answer:

1.46x10^{23}molecules \ LiNO_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3

Finally, by using the Avogadro's number we are able to compute the molecules:

0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3

Best regards.

5 0
4 years ago
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Which of the following answers is true for the following statement?
Vsevolod [243]

it is either "aweak acid or a lousy (or very weak) acid"

6 0
3 years ago
Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
Sergio [31]

Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}

4 0
4 years ago
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