Answer is c=12 on edge 2020
Answer:
The required probability is 0.988.
Step-by-step explanation:
Consider the provided information.
Based on a poll, 67% of Internet users are more careful about personal information when using a public Wi-Fi hotspot.
That means the probability of more careful is 0.67
The probability of not careful is: 1-0.67 = 0.33
We have selected four random Internet users. we need to find the probability that at least one is more careful about personal information.
P(At least one careful) = 1 - P(None of them careful)
P(At least one careful) = 1 - (0.33×0.33×0.33×0.33)
P(At least one careful) = 1 - 0.012
P(At least one careful) = 0.988
Hence, the required probability is 0.988.
The result may be higher because of the convenience bias in retrieving the sample. Because the survey subjects volunteered to respond not random.
<u>Answer:</u>
The correct answer option is A. Loss of 9 oz.
<u>Step-by-step explanation:</u>
We are given that a cat's weight change -8 oz. while she was sick. It means that the cat lost 8 ounces of weight.
We are to determine whether which of the given answer options show a greater change in weight.
The correct answer for this is: loss of 9 oz which is a greater loss than 8 oz.
Answer:
50/50
Step-by-step explanation: