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USPshnik [31]
3 years ago
13

Compute ????×????, where ????=????−2????+5????, ????=2????+????+3????. (Write your solution using the standard basis vectors ???

?, ????, and ????. Use symbolic notation and fractions where needed.)
Mathematics
1 answer:
Ahat [919]3 years ago
6 0

Given: ????=????−2????+5????

and ????=2????+????+3????

To find: We need to find the value of ????×????

Solution: Here given,

????=????−2????+5????

and ????=2????+????+3????

Therefore, solving these two we have, ????=0

So,????×????=0

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This season, Lisa's lacrosse team has won 2/3 of their home games (games played at Lisa's school), but just 2/5 of their away ga
denis23 [38]
The team has played 24 home games.
Let h be the number of home games and a be the number of away games.  The total number of games is 49; this gives ush+a=49
They won 2/3 of the home games and 2/5 of the away games; there were 26 games won.  This gives us2/3h + 2/5a = 26
In the first equation we isolate h by subtracting a from both sides:h+a-a=49-ah=49-a
Substitute this into the second equation:2/3(49-a)+2/5a = 26
Using the distributive property, we have2/3*49 - 2/3*a + 2/5a = 2698/3 - 2/3a + 2/5a = 26
Finding a common denominator to combine like terms, we have98/3 - 10/15a + 6/15a = 2698/3 - 4/15a = 26
We want to convert the whole number to thirds as well; 26 = 26*3/3 = 78/3:98/3 - 4/15a = 78/3
Subtracting 98/3 from both sides:98/3 - 4/15a - 98/3 = 78/3 - 98/3-4/15a = -20/3
Divide both sides by -4/15:a = -20/3 ÷ -4/15a = -20/3 × - 15/4 = 300/12 = 25
There were 25 away games.
This means there were 49-25 = 24 home games.
5 0
3 years ago
2+2-1 the kkkjdscdvxbcfvgbhnjimklimugytfdrseawzesxrctgvyhbjnkm
lilavasa [31]

Answer:

Hello! the answer is 3.......

I feel as though the question was a joke.. But no matter I will accept the points.

Anyway have a great day and take mental health breaks!

7 0
3 years ago
What is the answer for 2(a-b)-(b-a)
Kruka [31]
2(a - b) - (b - a) = 2a - 2b - b + a = 3a - 3b
7 0
3 years ago
Why does 5/3 not belong?
kupik [55]

Answer It's and improper fraction and should be 1 and 2/3

Step-by-step explanation:

three goes into five one time that's why there is a one in my answer. Because it only goes in once there is 2 left over so its left in the fraction form.

3 0
3 years ago
What functions have real zeros at 1 and 4
Sunny_sXe [5.5K]

Answer:

y=a(x^2-5x+4)

Step-by-step explanation:

I mean there are a bunch of answers. to figure it out, you can use the formula where you have solved the zeroes in terms of x.

y=(x-1)(x-4)

y=x^2-5x+4

Now if you add any a value to this function, your function will stretch or compress accordingly

y=a(x^2-5x+4)

So there isn't a single correct answer, but if you're looking for a bunch, then just replace the a value with whatever value you want, you'll still get the same answer since they're all proportional to one another.

8 0
3 years ago
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