All categories

2 years ago

Is there a outlier in the data set? Explain your reasoning.

Mathematics

1 answer:

Svetllana [295]2 years ago

4 0

Answer:

yes

Step-by-step explanation:

You might be interested in

In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of

arsen [322]

2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used

6 0

3 years ago

A man owns 3/4 of the share of a business and sells 1/3 of his

quester [9]

Given:

A man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.

To find:

The value of the business in Bir.

Solution:

Let x be the value of the business.

It is given that a man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.

$x\times \dfrac{3}{4}\times \dfrac{1}{3}=10000$

$x\times \dfrac{1}{4}=10000$

Multiply both sides by 4.

$x=4\times 10000$

$x=40000$

Therefore, the value of the business is 40,000 Bir.

3 0

2 years ago

The intersection of two streets forms a parallelogram. One street is 40 feet wide. The height of the parallelogram formed is 25

malfutka [58]

Answer:

1000

Step-by-step explanation:

4 times 25 =100 add anther 0 and it will be 1000

4 0

2 years ago

Read 2 more answers

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0

3 years ago

On Monday, Florencia's hair was h centimeters long. She got a haircut on Tuesday, so her hair was only 75% percent of the length

madam [21]

What is h?

maybe 25%

i hope it helped you sorry if it didn't

6 0

2 years ago

Read 2 more answers