Answer: 
Step-by-step explanation:
Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.
Event A is defined as drawing a white ball on the first draw.
Event B is defined as drawing a black ball on the second draw.
P(B|A) is expressed as the conditional probability of occurring B given that A.
i.e. it is the probability of happening B where A is already happended.
If a white ball is drawn at first, then the number of black ball(4) remains unchanged but the total number of balls (10) will become 9.
Then,
Answer: -3√5 + 10√3
Step 1: Find the prime factorization of the number inside the radical.
Step 2: Determine the index of the radical. In this case, the index is two because it is a square root, which means we need two of a kind.
Step 3: Move each group of numbers or variables from inside the radical to outside the radical. In this case, the pair of 2’s and 3’s moved outside the radical.
Step 4: Simplify the expressions both inside and outside the radical by multiplying.
You basically just have to do . . .
257/54
4.759 . . .
≈ 4.76 hours
Answer: 4.76 hours
Answer:
S={(heart), (diamond), (club), (spade)}
Step-by-step explanation:
In probability, a set is a well-defined collection of objects, product of an independent successful operation.
A sample space is the combination of all possible outcomes in an operation, so in this case, when we select one card and record the denomination, then we need to check what characteristic from the card are we looking for, from the problem we can see that is the denomination by itself, not the color, the number of the card, or anything else, and we only have 4 options of denomination so the sample space would be:
S={(heart), (diamond), (club), (spade)}
