The mass is 85.0g of Fe2O3
Sodium metal is quite reactive; sodium ions (as in NaCl) are quite unreactive. Cl^- ions are not reactive; they are stingily attracted to positive ions such as Na^+with which they form ionic bonds.
When given percents for an empirical formula problem, first consider all the percents as grams.
58.82% carbon —> 58.82 g carbon
27.45% nitrogen —> 27.45 g nitrogen
13.73% hydrogen —> 13.73 g hydrogen
Then convert the grams of all the elements to moles, based on their molar masses.
Carbon - 58.82 g / 12.01 g/mol = 4.898 mol carbon
Nitrogen - 27.45 g / 14.01 g/mol = 1.959 mol nitrogen
Hydrogen - 13.73 g / 1.008 g/mol = 13.62 mol hydrogen
Then divide all of the mole numbers by the smallest number of moles, which is in this case, the 1.959 mol of nitrogen.
Carbon - 4.898 / 1.959 = 2.5
Nitrogen - 1.959 / 1.959 = 1
Hydrogen - 13.62 / 1.959 = 7
You want whole numbers for all of your mole numbers, so multiply all of them by 2, since 2.5 isn’t a whole number.
Final answer: C5N2H14
Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate Glyceraldehyde 3-phosphate + DHAP
For the given reaction, is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T =
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = M
Glyceraldehyde 3-phosphate = M
DHAP = M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient =
Q =
=
Now, we will calculate the value of as follows.
=
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.
I wish I could help but I’m not sure sorry