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dolphi86 [110]
3 years ago
14

How do I solve this problem and check all the solutions?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0

Answer:

x-5=sqrt(2x+5)

then square both sides

x2-10x+25=2x+5

x2-8x+20=0

rest is trivial

Step-by-step explanation:

Sholpan [36]3 years ago
3 0

Answer:

x = 10

Step-by-step explanation:

Given

x - \sqrt{2x+5} = 5 ( subtract x from both sides )

- \sqrt{2x+5} = 5 - x ( divide all terms by - 1 )

\sqrt{2x+5} = x - 5 ( square both sides )

2x + 5 = (x - 5)²

2x + 5 = x² - 10x + 25 ( subtract 2x + 5 from both sides )

0 = x² - 12x + 20 ← in standard form

0 = (x - 2)(x - 10) ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 10 = 0 ⇒ x = 10

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions

x = 2

2 - \sqrt{4+5} = 2 - \sqrt{9} = 2 - 3 = - 1 ≠ 5

Thus x = 2 is an extraneous solution

x = 10

10 - \sqrt{20+5} = 10 - \sqrt{25} = 10 - 5 = 5 = right side

Thus x = 10 is the solution

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Which equation is perpendicular to 3x - y = 9 and goes through the point (6,6)
Lelechka [254]

Answer:

y = - \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

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6 0
3 years ago
Can someone help me with these please?
saul85 [17]

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b


Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.


To create point-slope form, we need to get one point from the graph. Let's use (3,0).

y = -\frac{4}{3}(x-3)


To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

y = -\frac{4}{3}x + 4


To get standard form, solve the equation in terms of C.


Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4



7 0
4 years ago
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