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Papessa [141]
3 years ago
10

Find gcf of 12 and 14 next use the gcf to factor 12 + 14

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

The GCF of 12 and 14 is 2,

Step-by-step explanation:

Use of GCF of 12 and 14

12 14 = 12 2 14 2 = 6 7 .

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Find the side length, c.
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Answer:

C=14.9

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Which determinants can be used to solve for x and y in the system of linear equations below?
NISA [10]
Are there choices? If there are, you should list them because there are some equivalents.
\left[\begin{array}{cc}4&16\\12&3\end{array}\right] \\  \left[\begin{array}{cc}-68&16\\21&3\end{array}\right] = x \\   \left[\begin{array}{cc}4&-68\\12&21\end{array}\right] = y \\

I'm assuming that you can solve these things. The top determinant comes to -180. The x value comes to - 540. When divided by the top one x = 3

The bottom determinant (y) comes to 900 and when divided by - 180 makes y = - 5. The checks out with actually solving the system of equations some other way.

3 0
3 years ago
Read 2 more answers
I need help with this fast! Thanks!
zavuch27 [327]

Answer: 8 1/20 or 8.05.

Step-by-step explanation: First you would want to make 9 3/4 - 2 1/5 to 39/4 - 11/5. We need to get the LCD or Least Common denominator of 4 and 5, which is 20. The rule is what you multiplied the denominator by you must multiply the numerator by, so our new equation is 195/20 - 44/20, which is 151/20. Now, we have to find the LCD of 2 and 20, which is 10. So 151/20 + 10/20 is 161/20 or 8 1/20.

4 0
3 years ago
Use the method of elimination to determine whether the given linear system is consistent or inconsistent. If it is consistent, f
S_A_V [24]

Answer:

Step-by-step explanation:

From the given information;

We will realize that in the 2nd & 3rd equation, the integer "x" is missing.

So, the correct equation should be:

4x - 2 + 6z = 0

x - y - z = 0

2x - y + 3z = 0

By rearrangement; if we switch equation (1) and (2)

x - y - z = 0      ----- (1)

4x - 2 + 6z = 0 ------ (2)

2x - y + 3z = 0  ------ (3)

If we multiply equation (1) and add that to  equation (2);

Then, we have:

x - y - z = 0

2y + 10z = 0

2x - y + 3z = 0

Also, if we multiply equation (1) by -2 and add that to equation (3), we have:

x - y - z = 0

2y + 10z = 0

y + 5z = 0

From above recent equation, if we swap equation (2) and (3);

x - y - z = 0

y + 5z = 0

2y + 10z = 0

Then, multiply equation (2) with -2, followed by adding it to equation(3);

Then:

x - y - z = 0

y + 5z = 0

0 = 0

Now, there exists no equation (3). Thus, let assume z = t to solve for x & y

y + 5z = 0

y = -5t

Similarly;

x - y - z = 0

x = -5t + t

x = -4t

Hence;

x = -4t; y = -5t; &  z = t

7 0
3 years ago
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