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3 years ago

9 is 12 percent of what number? ( show your work)

1 answer:

3 0

For this question, we want to find out what 9 / 12 equals as a percent or x / 100. Therefore, we have a proportion here and can say: 9/12 = x/100 Now, at this point, we can cross multiply to get: 900 = 12x Now, divide both sides by 12 to get x alone and find that: x = 75 <==== FINAL ANSWER
so 9 is 12% of 75!
I hope that helps you out! Please let me know if you have any other questions!

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Please helpppp it has to do with P(A U B)

Katyanochek1 [597]

$P(A)=0.5$ , $P(B)=0.6$ , $P(A\cup B)=0.8$

We find the probability of intersection using the inclusion/exclusion principle:

$P(A\cap B)=P(A)+P(B)-P(A\cup B)=0.3$

By definition of conditional probability,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{0.3}{0.6}=0.5$

For $A$ and $B$ to be independent, we must have

$P(A\cap B)=P(A)\cdot P(B)$

in which case we have $0.3=0.5\cdot0.6$ , which is true, so $A$ and $B$ are indeed independent.

Or, to establish independence another way, in terms of conditional probability, we must have

$P(A\mid B)\cdot P(B)=P(A)\cdot P(B)\implies P(A\mid B)=P(A)$

which is also true.

7 0

3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

4 years ago

Please help i'm so confused

umka21 [38]

Answer:

if it's bot raining, then it's sunny

8 0

3 years ago

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STatiana [176]

Answer:

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Step-by-step explanation:

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3 years ago

A small box of cereal weighs k grams. A jumbo box of cereal weighs 5 times as much.

mariarad [96]

Answer:

k=m/5

Step-by-step explanation:

explained in the attached pi

3 0

3 years ago