Answer:
Do y²-y¹/x²-x¹. So do 18-4/3-0 in order to get 14/3 and your slope intercept form! Hope this helped
Answer:
(a+b,c)
Step-by-step explanation:
Note that the midpoint formula is:

Point A (0,0) and Point C (2a+2b,2c)
It follows that:

Answer:
3.00156378e13
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:


Z = 1.16
Z = 1.16 has a p-value of 0.877.
0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
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