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3 years ago

9

The rate of change describes how the total cost changes with respect to time. Use this table to find the rate of change.

2 answers:

anygoal [31]3 years ago

8 0

Answer:

look below ⏬

Step-by-step explanation:

you can see there is a pattern

0.40

0.70

1.00

so you keep adding three (30)

1.30

1.60

1.90

And for 0

0.10

All in oder now

0- 0.10

10- 0.70

20- 1.00

30- 1.30

40- 1.60

50- 1.90

60- 2.20

worty [1.4K]3 years ago

4 0

My friend here justin his already taken and his craft at fort nite my guy ughhhh

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Autumn buys eggs and apples at the store.

soldier1979 [14.2K]

Answer:

$\frac{(5.76-34.14)}{6}$

Step-by-step explanation:

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2 years ago

Calculate the product: 4/5 x 55

Mars2501 [29]

4/5 x55
=4/5*55/1
=(4*55)/(5*1)
=220/5
=44/1
=44

5 0

3 years ago

Selecting an Instructor At a convention there are 7 mathematics instructors, 5 computer science instructors, 3 statistics instru

LiRa [457]

Answer:

11/19

Step-by-step explanation:

Firstly, we need to know the total number of instructors. This is equal to 7+5+4+3 = 19 instructors.

The probability of selecting a science instructor is 4/19

The probability of selecting a math instructor is 7/19

The probability of selecting either a science or a maths instructor is 4/19 + 7/19 = 11/19

4 0

4 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

PLEASE HELP! Brainliest will be given to the right answer

Bess [88]

The answer should be A

3 0

3 years ago

Read 2 more answers