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Luden [163]
3 years ago
15

The question is in the image h e l p m e​

Mathematics
2 answers:
kompoz [17]3 years ago
6 0

Answer:

The answer is D

Step-by-step explanation:

Line them up.

xxMikexx [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Option A is correct

10g^3-8g^2+10g^2+5g+12g-14

10g^3+2g^2+17g-14

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Katie is building a rectangular wall. The wall will be 332 bricks wide and 39 bricks tall. She has 15,000 bricks. Does she have
agasfer [191]
Katie has enough bricks because it only takes 12,948 bricks to build the wall. To get 12,948, you will multiply 332 by 39. So basically you are multiplying the width by how tall it is.
4 0
3 years ago
Read 2 more answers
What is 2/3d -8=1/2d
Brilliant_brown [7]

Answer:

d = 48

Step-by-step explanation:

4 0
3 years ago
Can two fractions with the same numerator and different denominators be equal?
Ede4ka [16]

Answer:

No

Step-by-step explanation:

You can only have the same denominator

Example:

2                3           5

-       +        -    =      -

9               9            9

8 0
3 years ago
Determine whether each given value of x satisfies the inequality x+1<x/3
Vinil7 [7]

x+1 < \dfrac{x}{3}\ \ \ \ |\cdot3\\\\3x+3 < x\ \ \ \ |-3\\\\3x < x-3\ \ \ \ |-x\\\\2x < -3\ \ \ \ |:2\\\\x < -1.5

Answer: (c) x = -4

5 0
3 years ago
2v^2-12 =-12v <br> Would really appreciate it loves❤️
Black_prince [1.1K]

For this case we have the following equation:

2v ^ 2-12 = -12v

Rewriting we have:

2v ^ 2 + 12v-12 = 0

Dividing by 2 to both sides of the equation:

v ^ 2 + 6v-6 = 0

We apply the quadratic formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

We have to:

a = 1\\b = 6\\c = -6

Substituting:

x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}

Thus, we have two roots:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

ANswer:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

7 0
3 years ago
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