Question

A triangle with vertices (0,0), (3,6), (7,4) is dilated by a factor of 3 with its center at the origin.

Answer 1

Answer:

$A' = (0,0)$

$B'= (9,18)$

$C'= (21,12)$

Step-by-step explanation:

Given

$A= (0,0)$

$B= (3,6)$

$C= (7,4)$

$k = 3$ -- dilation factor

Required

Determine the coordinates of the new triangle

This is calculated using:

$New = Old * k$

So, we have:

$A' = A *3$

$A' = (0,0) *3$

$A' = (0,0)$

$B' = B * 3$

$B'= (3,6)*3$

$B'= (3*3,6*3)$

$B'= (9,18)$

and

$C' = C * 3$

$C'= (7,4)*3$

$C'= (7*3,4*3)$

$C'= (21,12)$