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Dmitrij [34]
3 years ago
14

Please help me answer I will give 13 points thanks

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

y=85x

Step-by-step explanation:

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Which expression represents the following calculation?
____ [38]

Answer:

(381-22)*16

Step-by-step explanation:

(381-22)*16

3 0
3 years ago
Read 2 more answers
What is another solution of the equation<br><br> x + y = 7?
White raven [17]
X=3, y=4
x=-2, y=9
Set x equal to anything, then isolate y to get the other number.
5 0
4 years ago
First correct response gets brainliest
Simora [160]

Answer:

x = 13

Step-by-step explanation:

This question is based on Secant Secant theorem.

Secant Secant theorem gives us the following formula:

(AB + BD)AB = (AC + CE).AC

From the above question we have the following parameters

AB = 5

BD = x

AC = 7.5

CE = 4.5

Hence,

(AB + BD)AB = (AC + CE).AC

(5 + x)5 = (7.5 + 4.5)7.5

25 + 5x = 90

Collect like terms

5x = 90 - 25

5x = 65

x = 65/5

x = 13

5 0
3 years ago
How can I find the co-ordinatie of their point of intersection?
alisha [4.7K]
Combine the two equations so that it’s 2x+5=4x-1 and then subtract 2x from both sides. now it’s 5=4x-1 and add 1 to both sides. now is 6=4x 6 divided by 4 is 1.5 so that is the x value. now sub 1.5 as the x value into the first equation so it’s y=2(1.5)+5. you do the math and it’s y=8 (because 1.5 times 2 is 3 and 3+5 is 8) then your point is (1.5,8)
4 0
3 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
4 years ago
Read 2 more answers
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