Ask question

Ask question

All categories

Aleonysh [2.5K]

3 years ago

12

WILL GIVE BRAINLYEST

2 answers:

Svetach [21]3 years ago

6 0

Answer:

well it uses the compound interest formula

F(x) = P_{0}(1 + \frac{r}{100})^x

so in your question

x = time in years for the initial formula

P_{0} = 293,.... r = 6% ...and...

then you need to substitute x = 4

simplify the brackets and you should get the answer.

kramer3 years ago

6 0

Answer:

f(x)=293(1.06)^x;370

You might be interested in

Question 1 (1 point)

Firdavs [7]

Answer:

B. false

Step-by-step explanation:

Square units

I hope that is useful for you :)

6 0

3 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

Jacob can take any one of three routes from school to the mall, and one of five possible routes from the mall to his house. If h

nekit [7.7K]

Answer:

15 routes

Step-by-step explanation:

3 x 5 = 15 routes

8 0

2 years ago

A bag of rice weights 3.18 lbs find its mass in kilograms

Tamiku [17]

$\bf \begin{array}{ccll}
lbs&kgs\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2.2&1\\
3.18&k
\end{array}\implies \cfrac{2.2}{3.18}=\cfrac{1}{k}\implies k=\cfrac{3.18\cdot 1}{2.2}$

3 0

3 years ago

The population of Williston is currently 21,200 people. If the population

Pachacha [2.7K]

$21200 + 415(y)$

$27000 = 21200 + 415(y)$

$27000 - 21200 = 21200 - 21200 + 415(y)$

$5800 = 415(y)$

$\frac{5800}{415} = \frac{415(y)}{415}$

$13.9759..... = y$

$it \: will \: take \: about \: 14.0 \: years$

8 0

3 years ago