All categories

3 years ago

Line that passes (4,2) & (0,6)

Mathematics

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:

y=-x+6

Step-by-step explanation:

You might be interested in

Equivalent fraction for 5/14

damaskus [11]

Answer:

10/28

(one of many possible correct answers)

Step-by-step explanation:

5/14

Multiply by numerator and denominator by 2

10/28

3 0

3 years ago

I have 5 blue pants and 6 pants with a zipper. If I have 9 pants that are either blue or have a zipper or both, how many pants a

sveta [45]

Answer:

Step-by-step explanation:

Blue pants: 5

Zipper pants: 6

total amount of pants (blue, zipper or both): 9

to find the pants that have both qualities, we need to find the difference between the total amount of pants and the sum of the blue and zipper pants:

sum of blue and zipper pants: 5 + 6 = 11

you can tell that there is a difference of

11 - 9 = 2 pants

this means that these 2 pants belong to both categories (blue and with a zipper). Thus there are 2 pants that are blue and have a zipper

8 0

3 years ago

A standard die is rolled twice what is the probability of rolling a 3 and a 5

mafiozo [28]

Answer:

It is a 1/6 chance

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Rusty has 74 foot piece of rope that he needs to cut into two equal pieces how long will each piece be

denis-greek [22]

I'm just gonna say 37 feet each due to it being 74ft to begin with.
Simple math xd

4 0

3 years ago

Read 2 more answers

Let X denote the number of bars of service on your cell phone whenever you are at an intersection with the following probabiliti

ZanzabumX [31]

Answer:

a. $P(2 \leq X \leq 3) = 0.5$

b. $P(X \geq 1) = 0.9$

c. $P(X < 2) = 0.25$

d. $P(X > 3) = 0.25$

Step-by-step explanation:

We are given the following distribution:

$P(X = 0) = 0.1$

$P(X = 1) = 0.15$

$P(X = 2) = 0.25$

$P(X = 3) = 0.25$

$P(X = 4) = 0.15$

$P(X = 5) = 0.1$

a. Two or three bars

$P(2 \leq X \leq 3) = P(X = 2) + P(X = 3) = 0.25 + 0.25 = 0.5$

Thus:

$P(2 \leq X \leq 3) = 0.5$

b. At least one bar

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1 = 0.9$

Thus:

$P(X \geq 1) = 0.9$

c. Fewer than two bars

$P(X < 2) = P(X = 0) + P(X = 1) = 0.1 + 0.15 = 0.25$

Thus:

$P(X < 2) = 0.25$

d. More than three bars

$P(X > 3) = P(X = 4) + P(X = 5) = 0.15 + 0.1 = 0.25$

Thus:

$P(X > 3) = 0.25$

7 0

3 years ago