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3 years ago

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Suppose a least squares regression line is given by y= 4.302x - 3.293. What is the mean value of the response variable if x = 20

?

1 answer:

Iteru [2.4K]3 years ago

6 0

Answer:

i think this is the answer

Step-by-step explanation:

$4.302(20) - 3.293 = 82.747$

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A racquetball club charges $10 for a one-month trial membership. After the trail month, the regular membership fee is $12 per mo

Furkat [3]

Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months

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3 years ago

Write the product form of 3 a² b ³<br>

kifflom [539]

Answer:

a³-b³= (a-b)(a²+ab+ b²)

Step-by-step explanation:

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2 years ago

Solve 5x3/4 as a mixed number, plz

lana [24]

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3 years ago

Property taxes are based on an assessed value of $132,000 and the tax rate is 8.5 mills. The property closes on Jun 14. On a bas

defon

Answer:

$132,000 X .0085 = $1,122 / 360 = $3.1166 X 164 = $511.13

One mill is one dollar per $1,000 dollars of assessed value.

In our case 8.5 mills equivalent to 0.0085.

So to get the assessed value for one day

we will get

$132,000 X .0085 = $1,122 / 360 = $3.1166

Now we have the value for one day,

For June 14, we will calculate the days from January 1st to date

total days are 164. i.e. 5*30+14 = 164

Finally, the seller owes

$3.1166 * 164 = 511.13

6 0

3 years ago

The computer center at Rockbottom University has been experiencing computer downtime. Let us assume that the trials of an associ

Vinvika [58]

Answer:

The probability of the system being down in the next hour of operation is 0.3.

Step-by-step explanation:

We have a transition matrix from one period to the next (one hour) that can be written as:

$T=\left[\begin{array}{ccc}&R&D\\R&0.7&0.3\\D&0.2&0.8\end{array}\right]$

We can represent the state that system is initially running with the vector:

$S_0=\left[\begin{array}{cc}1&0\end{array}\right]$

The probabilties of the states in the next period can be calculated using the matrix product of the actual state and the transition matrix:

$S_1=S_0\cdot T$

That is:

$S_1=S_0\cdot T= \left[\begin{array}{cc}1&0\end{array}\right]\cdot \left[\begin{array}{cc}0.7&0.3\\0.2&0.8\end{array}\right]= \left[\begin{array}{cc}0.7&0.3\end{array}\right]$

With the inital state as running, we have a probabilty of 0.7 that the system will be running in the next hour and a probability of 0.3 that it will be down.

7 0

3 years ago