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2 years ago

12

Why did the Mountain Men era come to an end?

1 answer:

IceJOKER [234]2 years ago

3 0

I think the answer is D. The U.S. passed laws protecting the beaver.

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What fraction is halfway between 9/10 and 10/10. Question 8

Bumek [7]

$\frac{-9.5}{10}$ is halfway between $\frac{-9}{10}$ and $\frac{10}{10}$ .

hope that helps :)

5 0

3 years ago

What is 1/2 divided by 6?

jok3333 [9.3K]

Answer:

1/12 or 0.0833

Step-by-step explanation:

1/2 divided by 6

1/2x6

1/12!

7 0

3 years ago

Read 2 more answers

What 30000.48978 rounded up

Fudgin [204]

Answer:

Rounded to the nearest ones: 30000

Rounded to the nearest tenths: 30000.5

Rounded to the nearest hundredths: 30000.49

Rounded to the nearest thousandths: 30000.490

Rounded to the nearest ten-thousandths: 30000.4898

7 0

2 years ago

The coordinates of point D are (7, 4) and the coordinates of point E are (1, −3) . What is the slope of the line that is perpend

Katarina [22]

The slope of a line is given by the change in y coordinates over the change in x coordinate.
The slope of line DE will be (4 - -3)/ (7-1) = 7/6
If M1 and M2 are slopes of two perpendicular lines at a point then
M1× M2 = -1
Thus, the slope of a perpendicular to line DE will be -6/7.

7 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago