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Vsevolod [243]
3 years ago
6

Does someone know how to solve this problem?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4   b = 7   c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
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Answer:

The rocket will reach its maximum height after 6.13 seconds

Step-by-step explanation:

To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height

∵ y is the height of the rocket after launch, x seconds

∵ y = -16x² + 196x + 126

- Differentiate y with respect to x

∴ y' = -16(2)x + 196

∴ y' = -32x + 196

- Equate y' by 0

∴ 0 = -32x + 196

- Add 32x to both sides

∴ 32x = 196

- Divide both sides by 32

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

∴ The rocket will reach its maximum height after 6.13 seconds

There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = -\frac{b}{2a} and k is the value of y at x = h and k is the maximum/minimum value

∵ a = -16 , b = 196

∴ h=-\frac{196}{2(-16)}

∴ h = 6.125

∵ h is the value of x at the maximum height

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

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