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3 years ago

Does someone know how to solve this problem?

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4 b = 7 c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

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2 years ago

Can anyone help me I don’t understand plz

Citrus2011 [14]

There we have an information of two functions $g(t)\, and \, h(t)$

Using this two functions $g(t)\, and \, h(t)$ , we need to find the composition of functions (h\circ g)(t).

The composition of two functions h and g is the new function , by performing g first and then performing h.

$(h\circ g)(t)=h(g(t))$

$g(t)=3(t+1)$

$h(t)=2t$

Composition of h and g (t) = $(h\circ g)(t)$

$=h(g(t))$

First plugin the value of $g(t)=3(t+1)$

$h(g(t))=h(3(t+1))$

$=h(3t+3)$

We know that $h(t)=2t$ , we need to find h(3t+3),

That is, to replace t by 3t+3,

$=2(3t+3)$

Now distribute 2 into 3t+3,

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3 years ago

Read 2 more answers

Let logb A= 3; logb C = 2; logb D=5 What is the value of logb D^2/C^3A

Ne4ueva [31]

Answer:

The value of given log function is 1 .

Step-by-step explanation:

Given as :

Logb A = 3

Logb C = 2

Logb D = 5

Now from log property

if , Logb x = c , then x = $b^{c}$

So,

Logb A = 3 , then A = $b^{3}$

Logb C = 2 , then C = $b^{2}$

Logb D = 5 , then D = $b^{5}$

Now, According to question

$Logb\frac{D^{2}}{C^{3}A}$

So, $Logb\frac{(b^{5})^{2}}{(b^{2})^{3}\times b^{3}}$

Or, $Logb\frac{b^{10}}{b^{6}\times b^{3}}$

or, $Logb\frac{b^{10}}{b^{9}}$

Now, since base same So,

$log_{b}b^{10-9}$

∴ $log_{b}b^{1}$

Now log property

$log_{b}b$ = 1

Hence The value of given log function is 1 . answer

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3 years ago

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2 years ago

a taxi ride costs 40 dollars for the first 500 meters and each additional 300 meters (or a fraction thereof) adds $3.50 to the f

Colt1911 [192]

Answer:

$ 71.5

Step-by-step explanation:

firstly kilometer to meters

1 km = 1000 m

therefore 3 km = 3000m

for the first 500 = $40

hence deduct the 500 from 3000m

3000 - 500 = 2500

now find out how many 300m go into 2500

2500 / 300 = 8.33

which is rounded up to 9

therefore the total amount is :

40 + 9 * 3.5

= $71.5

5 0

2 years ago