Its is true that C ⊆ D means Every element of C is present in D
According to he question,
Let C = {n ∈ Z | n = 6r – 5 for some integer r}
D = {m ∈ Z | m = 3s + 1 for some integer s}
We have to prove : C ⊆ D
Proof : Let n ∈ C
Then there exists an integer r such that:
n = 6r - 5
Since -5 = -6 + 1
=> n = 6r - 6 + 1
Using distributive property,
=> n = 3(2r - 2) +1
Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then
Let s = 2r - 2
Then, m = 3r + 1 with r some integer and thus m ∈ D
Since , every element of C is also an element of D
Hence , C ⊆ D proved !
Similarly, you have to prove D ⊆ C
To know more about integers here
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She will need 3.77 pieces of wood because 1 piece is 6m which is 600 cm and she need 78 pieces of 29 cm so 78*29=2262 then you divide the by 600 and that gives you 3.77 so she realy need 4 sorry i f i got it wrong.
the answer either 3.77
or 4
Find the greatest common factor
in this case it would be 8, so she'd be able to make 8 packets maximum
Answer:
Emily gets 35 marbles and Asif gets 7 marbles.
Step-by-step explanation:
let 5x and x be marbles Emily and Asif get.
5x + x = 42
or, 6x = 42
or, x= 7
5x = 5×7=35
x =7
9514 1404 393
Answer:
₹ 30000
Step-by-step explanation:
The simple interest formula is ...
I = Prt . . . . . . principal P invested at rate r for t years
Fill in the values you know, and solve for the one you don't know.
9000 = P(0.06)(5)
9000/0.30 = P = 30000
The principal that will give ₹9000 in interest is ₹30000.
