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Georgia [21]
3 years ago
8

Nhiệt dung riêng của một chất là ?

Physics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

enchantment table language

Explanation:

satela [25.4K]3 years ago
4 0
Enchantment Language table
You might be interested in
Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressur
Natalka [10]

Answer:  a. 17.7 KJ/Mol

b. T=210K

Explanation:

Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.

the question isnt completely originally, but we could look at the likely derivation from the questions

(a) the standard enthalpy of vaporization

using the clausius clapeyron equation

In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )

In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )

Therefore, Delta H (vap) = 17.7 KJ/Mol

b. Also the boiling point

What is the normal boiling point of arsine?

At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr

substitution into the equation as stated in question 1

ln(760/253)=17700/8.314(1/189.55-1/T)

T=210K

5 0
3 years ago
Tarzan, who weighs 849 N, swings from a cliff at the end of a 18.0 m vine that hangs from a high tree limb and initially makes a
loris [4]

Answer:

Part a)

T = 342.5 \hat i + 675\hat j

Part b)

F_{net} = 342.5\hat i - 174\hat j

Part c)

F = 384.2 N

Part d)

\theta = 333 degree

Part e)

a = 4.4 m/s^2

Part f)

\theta = 333 degree

Explanation:

Part a)

Magnitude of tension force is given as

T = 757 N at 26.9 degree with vertical

T = 757 sin26.9 \hat i + 757 cos26.9 \hat j

T = 342.5 \hat i + 675\hat j

Part b)

Net force on Tarzen is given as

F_{net} = T + F_g

F_{net} = 342.5 \hat i + 675\hat j - 849 \hat j

F_{net} = 342.5\hat i - 174\hat j

Part c)

magnitude of the force is given as

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{342.5^2 + 174^2}

F = 384.2 N

Part d)

Direction of the force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{-174}{342.5}

\theta = 333 degree

Part e)

Magnitude of the acceleration

a = \frac{F}{m}

m = \frac{849}{9.81} = 86.5 kg

tex]a = \frac{384.2}{86.5}[/tex]

a = 4.4 m/s^2

Part f)

Direction of acceleration is same as the direction of the force

\theta = 333 degree

6 0
3 years ago
20 m
liubo4ka [24]

Answer:

  1.9 km​

Explanation:

The equation for vertical motion is ...

  h(t) = -4.9t^2 +26t +20

This will have a zero near t = 5.988 seconds.*

The horizontal distance traveled in that time is ...

  (310 m/s)(5.988 s) ≈ 1856 m ≈ 1.9 km

_____

* The root of a quadratic can be found numerous ways. We choose the quick and easy: let a graphing calculator show it to you.

5 0
4 years ago
Instruments on board the trmm (tropical rainfall measuring mission) satellite show 3d images of very tall rain columns called __
Ket [755]
These columns are called hot towers
7 0
3 years ago
A diamond with a mass of 45 g hangs motionless from a chain. what is the upward force of the chain on the diamond?
BARSIC [14]
The upward force of the chain on the diamond would be the tension in the chain, and this tension would have to support the weight of the 45g that hangs from the chain.

mass = 45 g = 45/1000 kg = 0.045kg

Weight = mg = 0.045 * 10 ≈ 0.45N,            g ≈ 10 m/s²

So the upward force is ≈ 0.45N. 
7 0
4 years ago
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