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zvonat [6]
2 years ago
10

Why do you see something as white, black, or another specific color

Physics
2 answers:
larisa86 [58]2 years ago
8 0

     We see something as white, black, or another specific color because the object is reflecting light waves back.

     In a nutshell; If we view an object as red, then the object is:

-> reflecting back red light waves

-> absorbing blue, green, etc light waves.

    What about white and black?

We see white when most all of the light is reflected.

When there is little to no light reflected, we see black.

n200080 [17]2 years ago
8 0

Answer:

When nearly all light is reflected, you see white. When no light is reflected, you see black.

Explanation:

You might be interested in
how do Swati and Banks adjust their body position during a skydiving jump so they can fall at the same rate
professor190 [17]

While skydiving, its not just freely falling under Earth's gravity. Additional force called drag acts against the gravity which slows down the rate of fall. Drag is caused by the air molecules which pushes against the body as it falls through them. This is actually a significant amount of force which slows down the rate of fall of the body. Drag depends on the contact surface area and weight. More the surface area in contact, more would be the drag. The sitting position of the skydiver would experience less drag than the chest down position because of the less contact surface area of the body with the air molecules while in the former case. No two persons have identical body shape and weight. Hence, the rate of fall can be made nearly equal but not exactly equal. This is would be possible when they are having same body position.

3 0
3 years ago
A 15 m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60° angle with horizontal. (a) Find t
scoray [572]

Answer:

a)    F₁ = 267.3 N,   N₁ = 1300 N,  b)    μ = 0.324

Explanation:

For this exercise we use the rotational equilibrium condition, we have a reference system is the floor and the anticlockwise rotations as positive, in the adjoint we can see a diagram of the forces

           

let's use subscript 1 for the ladder and 2 for the firefighter

            ∑ τ = 0

          -W₁ x₁ - W₂ x₂ + N₁ y = 0

           N₁ = \frac{W_1 x_1 + W_2 x_2}{y}          (1)

the center of mass of the ladder is at its geometric center,

d = L / 2 = 15/2 = 7.5 m

         cos 60 = x₁ / d₁

         x₁ = d₁ cos 60

         x₁ = 7.5 cos 60

         x₁ = 3.75 m

for the firefighter d₂ = 4 m

         cos 60 = x₂ / d₂

         x₂ = d₂ cos 60

          x₂ = 4 cos 60 = 2 m

for the fulcrum d₃ = 15 m

         sin 60 = y / d₃

         y = d₃ sin 60

         y = 15 sin 60

         y = 13 m

we look for the Normal by substituting in equation 1

         N₂ = \frac{500 \ 3.75 \ + 800 \ 2}{13}

         N₂ = 267.3 N

now let's use the translational equilibrium relations

 X axis

           F₁ - N₂ = 0

           F₁ = N₂

           F₁ = 267.3 N

Axis y

          N₁ - W₁ -W₂ = 0

          N₁ = W₁ + W₂

          N₁ = 500 + 800

          N₁ = 1300 N

b) for this case change the firefighter's distance d₂ = 9 m

          x₂ = 9 cos 60

          x₂ = 4.5 m

we substitute in 1

          N₂ = \frac{500 \ 3.75 \ + 800 \ 4.5}{13}  

          N₂ = 421.15 N

of the translational equilibrium equation on the x-axis

          fr = F₁ = N₂

          fr = 421.15 N

friction force has the expression

          fr = μ N

in this case the reaction of the Earth to the support of the ladder is N1 = 1300N

          μ = fr / N₁

          μ = 421.15 / 1300

          μ = 0.324

8 0
2 years ago
Which of the following graphs best represents the relationship between the gravitational potential energy of a freely falling ob
VLD [36.1K]

Answer:

The last graph.

Explanation:

Gravitational potential energy is the energy possessed by a body at a given height from the Earth's surface.

The formula to find the gravitational potential energy is given as:

U=mgh

Where, 'U' is the gravitational potential energy.

'm' is the mass of the body.

'g' is the acceleration of the body due to gravity.

'h' is the height of the body above the Earth's surface.

So, from the above equation, it is clear that, gravitational potential energy is directly proportional to the height. So, as height increases, the gravitational potential energy increases. At the surface of Earth, where, height is 0, the gravitational potential energy is also zero.

Therefore, the correct graph is a straight line with positive slope and passing through the origin. So, the last option is the correct one.

3 0
3 years ago
What is the acceleration of a 68 kg block of
S_A_V [24]

Answer:

Explanation:

Formula of acceleration a = fm

A = 68 x 386

= 26248

8 0
3 years ago
An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, starting a
Archy [21]

Answer:

Explanation:

Given that  

speed u=4×10⁶ m/s

electric field E=4×10² N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates

acceleration a=qE/m=1.6×10⁻¹⁹×4×10²/9.1×10⁻³¹=0.7×10¹⁴=7×10¹³ m/s

now we find the horizantal distance travelled by electrons hit the plates

horizantal distance X=u[2y/a]^1/2

=4×10⁶[2×2×10⁻²/7×10¹³]^1/2

=9.5cm

now we find the velocity f the electron strike the plate

v²-(4×10⁶)²=2×7×10¹³×2×10⁻²

v²=16×10¹²+28×10¹¹

v²=1.88×10¹³m/s

speed after hits =>V=4.34×10⁶ m/s

7 0
3 years ago
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