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2 years ago

Why do you see something as white, black, or another specific color

Physics

2 answers:

larisa86 [58]2 years ago

8 0

We see something as white, black, or another specific color because the object is reflecting light waves back.

In a nutshell; If we view an object as red, then the object is:

-> reflecting back red light waves

-> absorbing blue, green, etc light waves.

What about white and black?

We see white when most all of the light is reflected.

When there is little to no light reflected, we see black.

n200080 [17]2 years ago

8 0

Answer:

When nearly all light is reflected, you see white. When no light is reflected, you see black.

Explanation:

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Measuring the diameter of a specific object might include which pair of SI units

VLD [36.1K]

Well, the diameter of a circle is simply a length, so your measurement will have units of length. We just have to find an answer that has only units of length.

A). gram, second . . . mass and time. That can't be it.

B). kilogram, ampere . . . mass and current. That can't be it.

C). centimeter, meter . . . both lengths. This one is looking good.

D). candela, mole . . . light intensity and some chemical thing. That can't be it.

So it can't be anything else on this list but <em>C</em> .

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3 years ago

Energy from various sources is considered to have been derived from sun.Do you agree?Do justify.

Kruka [31]

Yes! with out the sun plants and animals wouldnt live right? therefore they get energey wich is passed on by food

3 0

3 years ago

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

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2 years ago

Calculate Kinetic Energy The potential energy of a swing is 200 J

RUDIKE [14]

Answer:

150J

Explanation:

Pi = Pf + Kf

200 = 50 + Kf

---> Kf = 150J

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2 years ago

If the atoms of one object (initially neutral) have electrons rubbed off through friction with a second object, the first object

snow_lady [41]

Positive. The 1st object loses electrons and will thus have an imbalance of charge with loss of electrons.

4 0

3 years ago